Answer: A=2πrh+2πr2
Hope this helps you out! :}
Answer: look at the picture
Step-by-step explanation: hope this help
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
From the first equation,
x+5 = 3(y+5)
x = 3y + 15 - 5
Now substitue x in the second equation with (3y +15 - 5).
x-5 = 7(y-5)
(3y+15-5) - 5 = 7(y-5)
3y +5 = 7y - 35
-4y = - 40
y = 10
Since y is 10, and x is (3y +15 - 5),
x = 30 + 15 - 5 = 40
Answer: 18.7
Step-by-step explanation:
Find the lengths of AB, BC, and CA
AB =
= 5
≈ 7.1
BC =
= 5
≈ 7.1
CA =
= 2
≈ 4.5
7.1 + 7.1 + 4.5 = 18.7