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2 years ago

11

Y=-x-4

1 answer:

aliina [53]2 years ago

5 0

Answer:

(-4 , 0)

Step-by-step explanation:

Graph attached

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A scientest is studying a new super bacteria that is threatening to cause an outbreak. On the first day, there were 5 organisms

ElenaW [278]

Answer:

C. 125

Step-by-step explanation:

Given:

Bacteria on day 1 = 5

On day 2, each bacteria got split into 5.

So, number of bacteria on day 2 = $5\times 5 = 25$

Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.

So, number of of bacteria on day 3 = $25\times 5 =125$

Therefore, the population of bacteria on day 3 is 125.

8 0

2 years ago

Anybody...Help!!!!!!!!!!!

Sloan [31]

Simple...

when they ask for the rate of change they ask for slope -->>

Using $\frac{ y_{1} - y_{2} }{ x_{1} - x_{2} }$ to find the rate of change for (-3,0) and (-2,-5)

$\frac{0--5}{-3--2}$

$\frac{0+5}{-3+2}$

$\frac{5}{-1}$

m=-5

Thus, your answer.

4 0

2 years ago

Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask

Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

$P(x=r)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

$P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}$

$=56(0.4)^5 (0.6)^3$

$=0.12386304$

(b) the probability of the number that say they would feel secure is more than five

$P(X>5) = P(X=6)+ P(X=7) + P(X=8)$

$=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}$

$=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8$

$=0.04980736$

(c) the probability of the number that say they would feel secure is at most five

$P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)$

$=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}$

$=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3$

$=0.95019264$

8 0

2 years ago

6) The population of rats doubles every 8 months. If there were 23 rats to start how many

taurus [48]

Answer:

736

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please help i will mark branliest

kotegsom [21]

Answer:

C

Step-by-step explanation:

5 0

2 years ago