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Anna71 [15]
3 years ago
10

A.42.6 square units B. 128 square units C. 32 square units D. 64 square units

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer:

Step-by-step explanation:

D. 64 square units

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If f(x)=8x+5, what is f(x)^-1?
Molodets [167]
F(8x+5)^-1=0.2

(8+5)^-1=0.077
5^-1=0.2
8x^-1=0.125
0.125-0.2=-0.075/0.2-0.125=0.075
7 0
3 years ago
5c squared- d squared+3/2c - 4d...c= -1. d= -4​
riadik2000 [5.3K]

For this case we have the following expression:

5c ^ 2-d ^ 2 + \frac {3} {2} c-4d

We must find the value of the expression when:

c = -1\\d = -4

Substituting we have:

5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}

Finally, the value of the expression is:

\frac {7} {2}

ANswer:

\frac {7} {2}

5 0
3 years ago
Which statement is true about discontinuities of the function ?
uysha [10]
The Second one hope it helped
3 0
3 years ago
Find the value of x.
Anni [7]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the exact length of the curve. y2 = 4(x + 1)3, 0 ≤ x ≤ 1, y > 0
mylen [45]
We can find this using the formula: L= ∫√1+ (y')² dx

First we want to solve for y by taking the 1/2 power of both sides:

y=(4(x+1)³)^1/2
y=2(x+1)^3/2

Now, we can take the derivative using the chain rule:

y'=3(x+1)^1/2

We can then square this, so it can be plugged directly into the formula:

(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9

We can then plug this into the formula:

L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765

The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
6 0
3 years ago
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