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Xelga [282]
3 years ago
13

In the diagram, GB = 2x + 3..

Mathematics
2 answers:
Sauron [17]3 years ago
8 0

Answer:

it's 15 on edge

Step-by-step explanation:

basically, you want to solve for x and substitute it for 2x+3,

Solving for x is

5x=2+18

3x=18

x=6

now getting GB

2(6)+3

12+3

15

Hope that helps

True [87]3 years ago
5 0

Answer:

<h2>10 units</h2>

Step-by-step explanation:

It's important to know that the centroid is always two-thirds of the median. Which means

AG=\frac{2}{3}FA\\ x+9=\frac{2}{3}(5x+x+9)\\ x+9=\frac{2}{3}(6x+9) \\x+9=4x+6\\9-6=4x-x\\3x=3\\x=1

Which means AG=x+9=1+9=10.

But, the centroid has always the same distance from each vertex, which means

AG=BG=10

Therefore, BG is 10 units long.

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You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
PLEASE HELP IF YOU CAN, ASAP :)
Luba_88 [7]

Answer:

I mean 6

Step-by-step explanation:

That is the answere to you question.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!
Zielflug [23.3K]
Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.



Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}

Let's plug this into this form first:
y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55

Now, let's make it into Standard Form.
y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
\boxed{f(x) = 85x + 55}

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
5 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is<br> 2x – 2y = 20.
Simora [160]

Answer:

-1

Step-by-step explanation:

Solve for y into y=mx+b

2x-2y=20

-2y=-2x+20

y=(-2x+20)/-2

y=x-10

the slope is m, so it’s 1

A line perpendicular to that would be -1

7 0
3 years ago
25. En cada par de triangulos, las marcas iguales indican elementos congruentes. ¿Que par de triangulos es congruentre segun el
Rama09 [41]

Answer:

i cant read spanish. sorry

Step-by-step explanation:

5 0
3 years ago
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