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Xelga [282]
3 years ago
13

In the diagram, GB = 2x + 3..

Mathematics
2 answers:
Sauron [17]3 years ago
8 0

Answer:

it's 15 on edge

Step-by-step explanation:

basically, you want to solve for x and substitute it for 2x+3,

Solving for x is

5x=2+18

3x=18

x=6

now getting GB

2(6)+3

12+3

15

Hope that helps

True [87]3 years ago
5 0

Answer:

<h2>10 units</h2>

Step-by-step explanation:

It's important to know that the centroid is always two-thirds of the median. Which means

AG=\frac{2}{3}FA\\ x+9=\frac{2}{3}(5x+x+9)\\ x+9=\frac{2}{3}(6x+9) \\x+9=4x+6\\9-6=4x-x\\3x=3\\x=1

Which means AG=x+9=1+9=10.

But, the centroid has always the same distance from each vertex, which means

AG=BG=10

Therefore, BG is 10 units long.

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\bold{\huge{\orange{\underline{ Solution }}}}

\bold{\underline{ Given \: Rules}}

  • <u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
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\bold{\underline{ Let's \: Begin}}

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }

\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}

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\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}

\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

\sf{ 158 + b = 166 + a, 156 + d = 166 + a }

\sf{ b = 166 - 158 + a,  d = 166 - 156 + a }

\sf{ b = 8 + a,  d = 10 + a ...(3)}

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\sf{ a = 189 - 166 }

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