1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dvinal [7]
2 years ago
12

LAST CHANCE! GIVING 100 POINTS AND BRAINLIEST TO WHOEVER ANSWERS THIS QUESTION WHATS 5+9+9

Mathematics
2 answers:
Pavlova-9 [17]2 years ago
8 0

Answer:

its 23

Step-by-step explanation:

k0ka [10]2 years ago
3 0

Answer:

23

Step-by-step explanation:

You might be interested in
Please help with 2 and 3 for maths
Vera_Pavlovna [14]

Answer:2-4=

Step-by-step explanation:y-16-(-42)

y-16+16

y-32

y-16-(-22)

y-16+4

y-20

y-16-(02)

y-16

y-16-(42)

y-0

8 0
2 years ago
Read 2 more answers
I need some help with this, I am supposed to solve for x
liq [111]

They are the same measurements, because:

from 10x + 5, first do vertical angle.

then, alternate interior angle,

then vertical angle again,

and another alternate interior angle.

For each vertical and alternate interior angles, the measurements stay the same.


Set them equal to each other, isolate and solve for x.

10x + 5 = 11x - 1

First, isolate the x. Subtract 10x from both sides, and add 1 to both sides

10x (-10x) + 5 (+1) = 11x (-10x) -1 (+1)

Simplify

5 + 1 = 11x - 10x

6 = x

x = 6

6 is your answer for x.

hope this helps

3 0
3 years ago
I will be marking brainliest please help me with these questions.
krek1111 [17]

Answer/Step-by-step explanation:

1. To find the area of the shaded region, you'd find the area of the white rectangular shape, next, find the area of the whole triangular shape, then find the difference of their areas to get the area of the shaded region. Thus, the formula to use would be:

Area of shaded region = area of triangle - area of rectangle

Area of shaded region = ½*base*height - length*width

1. a. Volume of triangular prism = area of triangular base * height of prism

Volume of triangular prism = ½bh * H

Where,

b = 6 m

h = 4 m

H = 8 m

Substitute

Volume of prism = ½*6*4*8

Volume of prism = 96 m³

b. Volume of sphere = ⁴/3πr³

Where,

r = 9 cm

Substitute

Volume = ⁴/3*π*9³

Volume = ⁴/3*π*729

Volume ≈ 3,053.6 cm³ (nearest tenth)

2. Use Pythagorean theorem to find the height of the cone

radius of the cone (r) = ½(16) = 8 cm

Slant height (l) = 11 cm

height (h) = ?

Using Pythagorean theorem, we have:

h = √(l² - r²)

Substitute

h = √(11² - 8²)

h = √(57)

h ≈ 7.5 cm (nearest tenth)

b. Volume of the cone = ⅓πr²h

where,

r = 8 cm

h = 7.5 cm

Volume = ⅓*π*8²*7.5

Volume = 502.7 cm³ (nearest tenth)

7 0
2 years ago
What is the approximate solution to this equation?
Sindrei [870]

Answer: b)

Step-by-step explanation:

3^3 is equal to 27 exactly, but it asks for an approximate. 27.55 is near 27 so yea, there ya go ^

5 0
3 years ago
Read 2 more answers
Which statement below correctly depicts the expected value of a fair game?
Mnenie [13.5K]
E(x)=0 will be your answer

3 0
3 years ago
Read 2 more answers
Other questions:
  • 4.2a - 3.5b - (1.8a + 2.7b - 1.9)
    10·1 answer
  • PLEASE HELP ME <br>Multiply the monomials: <br><br>a2x5b, −0.6axb2 and 0.6a2b3
    9·1 answer
  • A grocery store is selling 6 cans of cat food for $3. Write and solve a multiplication equation.
    9·1 answer
  • #10-12!!! look at picture!!! I don't give out points for free!!! T.T
    7·2 answers
  • A bat and a ball cost one dollar and ten cents in total. The bat costs a dollar more than the ball. How much does the ball cost?
    9·1 answer
  • There are 35 students in the drama club. 2 out of every 5 students in the club are boys.
    5·2 answers
  • Question 11 what is the naswer please fast​
    14·1 answer
  • Identify the solution set 2(-x -9) = -2x + 8
    12·1 answer
  • Which function is invertible? select EACH correct answer.
    5·1 answer
  • Help please! will give brainliest
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!