Answer:
y = -x² + 6x - 1
General Formulas and Concepts:
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Expanding by FOIL (First Inside Outside Last)
- Combining like terms
Step-by-step explanation:
<u>Step 1: Define equation</u>
y = -(x - 3)² + 8
<u>Step 2: Rewrite</u>
- Expand [FOIL]: y = -(x² - 6x + 9) + 8
- Distribute -1: y = -x² + 6x - 9 + 8
- Combine like terms: y = -x² + 6x - 1
Answer:
In a system, there are two linear inequalities. The solution to the system is all the points that satisfy both inequalities or the region in which the shading overlaps. Given the system of linear inequalities shown in the graph, let's determine which points are solutions to the system.
Hope this Helped!!!!!:)
Step-by-step explanation:
If tangent to the curve y = √x is parallel to the line y = 8x, then this implies that the tangent to y = <span>√x has the same slope as the line y = 8x. In other words, the derivative (slope) function of y = √x is equal to the slope of the line y = 8x, which is m = 8. Hence y' = 8 once we find y'
y = </span><span>√x = x^(1/2)
Applying the power rule and simplifying, we find that the derivative is
y' = 1/(2</span>√x)
Now remember that y' must equal 8
1/(2<span>√x) = 8
Multiplying both sides by 2</span><span>√x, we obtain
1 = 16</span><span>√x
Dividing both sides by 16, yields
</span><span>√x = 1/16
But wait a minute, √x = y. Thus 1/16 must be the y-coordinate of the point at which the tangent to y = √x is drawn.
Squaring both sides, yields
x = 1/256
This is the x-coordinate of the point on the curve where the tangent is drawn.
</span><span>∴ the required point must be (1/256, 1/16)
GOOD LUCK!!!</span>
