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The given question is incomplete. The complete question is as follows.
The solubility product of calcium fluoride () is at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?
Explanation:
Reaction equation for the given chemical reaction is as follows.
Therefore, expression for will be as follows.
=
Also, moles of per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]
=
=
Hence,
=
= M
Now, moles of per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]
=
= M
Also,
=
= M
Hence, ionic product =
=
=
As, the ionic product is less than the , this means that the fluoride will be soluble in water containing the calcium.