Answer:
d)carbon(iv)oxide/carbon(ii)oxide
e)Calcium,carbon,oxygen
f)carnonhydride
g)Carbonhydrate
h)hydrogen+oxygen
I)Iron sulphide
j)Magnesiumoxide
m)magnesium hydroxide+hydrogen gas
d)carbon dioxide
2. Left to right (smallest to largest) F-, Mg2+, Na+, and K+
5. Cs, Ga, As, N, O
6. Cs or H (probably cesium)
7. In or In 2+ (not sure which)
Hope this helps, I've never really seen questions like this before.
Answer : The final equilibrium temperature of the water and iron is, 537.12 K
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.


where,
= specific heat of iron = 560 J/(kg.K)
= specific heat of water = 4186 J/(kg.K)
= mass of iron = 825 g
= mass of water = 40 g
= final temperature of water and iron = ?
= initial temperature of iron = 
= initial temperature of water = 
Now put all the given values in the above formula, we get:


Therefore, the final equilibrium temperature of the water and iron is, 537.12 K
V = displacement /time
= 3/3 = 1km/hr