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Papessa [141]
3 years ago
9

2) __H,PO, +

Chemistry
1 answer:
Gnoma [55]3 years ago
4 0

Explanation:

a.H2PO4 + 2KOH = K2PO4 + 2H2O

b. H2PO4 _ 2KOH

1(2) + 31 + 16(4) _ 2(23) + 2(16) + 2(1)

2 + 31 + 64 _ 46 + 32 + 2

97 _ 80

no of moles of H2PO4 = 2.5 ÷ 97

= 0.026mol

no of moles of 2KOH = 4 ÷ 80

= 0.05mol

2KOH is the limiting reactant

c. H2PO4 is the excess reactant

d. 1 mole H2PO4 weighs 2.5g

0.026mol H2PO4 weighs g

(0.026 × 2.5)

H2PO4 weighed 0.065g after reaction

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How many atoms are in 6.7 moles of iron?
sineoko [7]

Answer:

4.034x10^24 atoms

Explanation:

6.7 x 6.023x10^23 = 4.034x10^24 atoms

6 0
2 years ago
Read 2 more answers
how many molecule of carbon dioxide are needed to react with excess iron oxide to produce 11.6 g of iron
lesya692 [45]

Answer:

0.16 moles of Carbon

Explanation:

The balanced reaction equation:

2Fe_{2}O_{3} + 3C → 4Fe + 3CO_{2}↑

The mole ratio of Carbon to Iron is 3 : 4 (since Fe2O3 is in excess)

i.e 3 moles of C produces 4 moles of Fe.

If 1 mole of Fe - 55.8g of Fe

? moles - 11.6g of Fe

= \frac{11.6}{55.8} = 0.208 moles

But 3 moles of C - 4 moles of Fe

? moles of C - 0.208 moles of Fe

= \frac{3 *0.208}{4} = 0.16 moles of carbon.

I hope this explanation was clear and useful.

5 0
3 years ago
Why do we call meteors shooting stars?
zlopas [31]

They burn up and cause it to look like shooting stars

6 0
3 years ago
Why must living things rely on thousands of catalysts for chemical reactions necessary for life?
just olya [345]
<span>It affects only one chemical reaction</span>
8 0
3 years ago
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What is the overall enthalpy of reaction for the equation shown below?
Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O      ΔH₁ = -483.6 Kj

        3O₂ => 2O₃        ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O       (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O        ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

          2O₃ => 3O₂           ΔH₂ = -284.6Kj              (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O         ΔH₁₂ = -1735.2 Kj       (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O            ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj    

4 0
3 years ago
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