Explanation:
a.H2PO4 + 2KOH = K2PO4 + 2H2O
b. H2PO4 _ 2KOH
1(2) + 31 + 16(4) _ 2(23) + 2(16) + 2(1)
2 + 31 + 64 _ 46 + 32 + 2
97 _ 80
no of moles of H2PO4 = 2.5 ÷ 97
= 0.026mol
no of moles of 2KOH = 4 ÷ 80
= 0.05mol
2KOH is the limiting reactant
c. H2PO4 is the excess reactant
d. 1 mole H2PO4 weighs 2.5g
0.026mol H2PO4 weighs g
(0.026 × 2.5)
H2PO4 weighed 0.065g after reaction
