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3 years ago

2) __H,PO, +

Chemistry

1 answer:

Gnoma [55]3 years ago

4 0

Explanation:

a.H2PO4 + 2KOH = K2PO4 + 2H2O

b. H2PO4 _ 2KOH

1(2) + 31 + 16(4) _ 2(23) + 2(16) + 2(1)

2 + 31 + 64 _ 46 + 32 + 2

97 _ 80

no of moles of H2PO4 = 2.5 ÷ 97

= 0.026mol

no of moles of 2KOH = 4 ÷ 80

= 0.05mol

2KOH is the limiting reactant

c. H2PO4 is the excess reactant

d. 1 mole H2PO4 weighs 2.5g

0.026mol H2PO4 weighs g

(0.026 × 2.5)

H2PO4 weighed 0.065g after reaction

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Answer:

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Explanation:

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Number of moles of CS2 = 1.00 mol

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Step 3: Calculate the limiting reactant

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Step 4: Calculate moles of CO2 and SO2

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Answer:

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ira [324]

Explanation:

Given that:

V1 = 50mL

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learn more:

Molarity brainly.com/question/9324116

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