Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer: the first one
Step-by-step explanation:
It is the only one that is right
Answer:
48
Step-by-step explanation:
25% is 1/4 of the bag. 12x4 = 48.
There are 48 jelly beans in the bag.
Hope that helps
Answer:
BC~=AD (GIVEN )
CBA=CDA (altanate angles BC=AD)
C=A (altanate angles (BC=AD)
AAS
brainyliest please
Answer: b commutative property
Step-by-step explanation: idid the test and i got it right
