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sladkih [1.3K]
3 years ago
13

If y varies directly with x and y = -15 when x = 3, find x when y = 10.

Mathematics
1 answer:
Anika [276]3 years ago
4 0

Answer:

like here x= 3 and y= -15

here, its 5 times goes in negative

now if y = 10 TO X IS 5 TIME POSITIVE HERE = 10×5 = 50

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How did World War II impact Louisiana's economy?
sladkih [1.3K]

Answer:

A.

Step-by-step explanation:

I took the K12 test and the answer is A.

7 0
3 years ago
Write the equation of the line perpendicular to y = 5/3x + 1 that passes through the point (- 8, 2)
xenn [34]

Answer:

y = - \frac{3}{5} x - \frac{14}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{5}{3} x + 1 ← is in slope- intercept form

with slope m = \frac{5}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{5}{3} } = - \frac{3}{5} , thus

y = - \frac{3}{5} x + c ← is the partial equation

To find c substitute (- 8, 2) into the partial equation

2 = \frac{24}{5} + c ⇒ c = 2 - \frac{24}{5} = - \frac{14}{5}

y = - \frac{3}{5} x - \frac{14}{5} ← equation of perpendicular line

4 0
3 years ago
Mrs. Ralph decides to rent a movie theatre for her students to celebrate the end of the trimester. The rental rate is $250 for t
timurjin [86]
5 and a half hours.

600-250 for the first two hours and it leaves her 350 for additional hours. divide 350 by 50 and you get 7. so she can get 7 extra half hours which is 3.5 hours.

so 2+3.5 is 5.5
5 0
3 years ago
Solve for Y 3y =2(4-2y)+6
Nat2105 [25]

Answer:

HOLA MATE HERE IS UR ANSWER:-

Step-by-step explanation:

  • 3y=2(4-2y)+6
  • 3y=8-4y+6
  • 3y=14-4y
  • 3y+4y=14
  • 7y=14
  • y=14/7
  • y=2
8 0
2 years ago
Integral of 1/(x^2-x+1) ​
Lunna [17]

\boxed{\sf \displaystyle{\int}x^ndx=\dfrac{x^{n+1}}{n+1}}

\\ \sf\longmapsto \displaystyle{\int}\dfrac{1}{x^2-x+1}

\\ \sf\longmapsto \displaystyle{\int}x^{-2}-x^{-1}+1

\\ \sf\longmapsto \displaystyle{\int}x^{-2}-\displaystyle{\int}x^{-1}+\displaystyle{\int}1

\\ \sf\longmapsto \dfrac{x^{-2+1}}{-2+1}-\dfrac{x^{-1+1}}{-1+1}+1

\\ \sf\longmapsto \dfrac{x^{-1}}{-1}-\dfrac{x^0}{0}+1

\\ \sf\longmapsto -\dfrac{1}{x}-\dfrac{1}{0}+1

\\ \sf\longmapsto -\dfrac{1}{x}-\infty+1

\\ \sf\longmapsto \infty

6 0
3 years ago
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