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lozanna [386]
3 years ago
15

I need help about this question of physics

Physics
2 answers:
kodGreya [7K]3 years ago
7 0

Answer:

D

Explanation:

Each notch is 1m,

60 kg 2m away is equal to 40 kg 3 m away

D is 3m away

Vika [28.1K]3 years ago
7 0
The correct answer is D
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Pulsars are neutron stars that emit X rays and other radiation in such a way that we on Earth receive pulses of radiation from t
stira [4]

Answer:

(a) a_{c} = 5.41\times 10^{9} m/s^{2}

(b) a_{t} = 2.99\times 10^{- 5} m/s^{2}

Given:

Time period of Pulsar, T_{P} = 33.085 ms == 33.085\times 10^{- 3} s

Equatorial radius, R = 15 Km = 15000 m

Spinning time, t_{s} = 9.50\times 10^{10}

Solution:

(a) To calculate the value of the centripetal  acceleration, a_{c} on the surface of the equator, the force acting is given by the centripetal force:

m\times a_{c} = \frac{mv_{c}^{2}}{R}

a_{c} = \frac{v_{c}^{2}}{R}                (1)

where

v_{c} = \frac{distance covered(i.e., circumference)}{ T}

v_{c} = \frac{2\pi R}{Time period, T}           (2)

Now, from (1) and (2):

a_{c} = R\frac({2\pi )^{2}}{T^{2}}

a_{c} = 15000\frac{2\pi )^{2}}{(33.085\times 10^{- 3})^{2}}

a_{c} = 5.41\times 10^{9} m/s^{2}

(b) To calculate the tangential acceleration of the object :

The tangential acceleration of the object  will remain constant and is given by the equation of motion as:

v = u + a_{t}t_{s} = 0

where

u = v_{c}

a_{t} = - \frac{2\pi R}{Tt_{s}}

a_{t} = - \frac{2\pi 15000}{33.085\times 10^{- 3}\times 9.50\times 10^{10}}

a_{t} = 2.99\times 10^{- 5} m/s^{2}

7 0
3 years ago
What is the formation of a shadow?
katovenus [111]

Answer:

Shadows are formed when an opaque object or material is placed in the path of rays of light. The opaque material does not let the light pass through it. The light rays that go past the edges of the material make an outline for the shadow

Explanation:

7 0
3 years ago
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If a 0.5kg cart is loaded with three 1.5-kg bricks, then the total mass of the loaded cart would be 5.0 kg. If it is moving with
s2008m [1.1K]
Momentum = mass x acceleration

5 x 2 = 10 kg. m/s
4 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the man

In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

6 0
3 years ago
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Vilka [71]
This is a trick question, isn't it? If a car is stuck in traffic, it doesn't matter how fast it can travel, because it isn't moving at all. Therefore the average speed would be zero, right?
7 0
4 years ago
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