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Leya [2.2K]
2 years ago
8

In ΔNOP, the measure of ∠P=90°, PN = 95 feet, and OP = 31 feet. Find the measure of ∠O to the nearest degree.

Mathematics
1 answer:
Eva8 [605]2 years ago
6 0

Given:

In ΔNOP, the measure of ∠P=90°, PN = 95 feet, and OP = 31 feet.

To find:

The measure of ∠O to the nearest degree.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Opposite}{Adjacent}

In triangle NOP,

\tan O=\dfrac{PN}{OP}

\tan O=\dfrac{95}{31}

O=tan^{-1}\dfrac{95}{31}

O=71.92768

O\approx 72

Therefore, the measure of angle O is 72 degrees.

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