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irina1246 [14]
1 year ago
9

What the closest volume of a cylinder with a height of 10 and a circumference of 8

Mathematics
1 answer:
jenyasd209 [6]1 year ago
3 0

In order to calculate the volume of a cylinder, we can use the following formula:

V=\pi r^2h

Where r is the base radius and h is the height.

If the circumference is 8, we have:

\begin{gathered} C=2\pi r \\ 8=2\pi r \\ r=\frac{4}{\pi} \end{gathered}

Now, calculating the volume, we have:

\begin{gathered} V=\pi(\frac{4}{\pi})^2\cdot10 \\ V=\frac{160}{\pi} \\ V=50.93 \end{gathered}

So the correct option is the second one.

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The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that m = 100, \mu = \frac{1}{100} = 0.01

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

P(X > x) = 0.08

So

e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

-0.01x = \ln{0.08}

x = -\frac{\ln{0.08}}{0.01}

x = 252.6

Capacity of 252.6 cubic feet per second

5 0
2 years ago
» Alexander has some watermelons. He gathers 13 more watermelons. He now has 62 watermelons.
Vilka [71]
Yeah but what is the question?
3 0
2 years ago
The average sunflower has 34 petals. What is the best estimate of the total number of petals on 57 sunflowers?
stellarik [79]
Your initial instinct would be to solve this problem with this solution. 34 x 57 = 1,938 petals.

However, the word estimate is present; therefore, we have to consider that we need to get the approximate number and not the exact number of petals.

There is a general rule regarding estimation or approximation. You have to round it to the nearest place you have based on. In this problem we round it off to the nearest tens place.

If the number is below 5, you round it down: 34 is rounded down to 30 petals.

If the number is above 5, you round it up: 57 is rounded up to 60 sunflowers.

Thus, your equation would be :  30 x 60 = 1,800 petals (best estimate)


3 0
3 years ago
If Sin 3x= Cos (x-60), find the value of x​
Kamila [148]

Answer:

x = 15

Step-by-step explanation:

Assuming 3x and x-60 are in degrees, you can use:

cos(a) = sin(a+90)

To rewrite the equation as:

sin(3x) = sin(x-60+90)

sin(3x) = sin(x+30)

3x = x+30

2x = 30

x = 15

But, solving 3x = x+30 which simplifies to x=15 is not the only solution to this equation, as you can see in below picture. Finding all solutions is a bit more work, but maybe that is not required in your case.

4 0
2 years ago
. The slope of the line is 4/9, and it contains the point (-6,8). Enter an equation in point-slope form
Serga [27]

Answer:

Step-by-step explanation:

m =4(-6, 8)/9

4 0
2 years ago
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