The function is

, and according to the description of the function in the problem statement, we have the following:
at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:

(ft), which is the initial height, as expected.
At t=1 (sec), the height would be

.
etc.
The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.
This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.
Answer: B) 7 sec
Answer:
1/8
Step-by-step explanation:
Answer:
∠ G = 26°, ∠ F = 154°
Step-by-step explanation:
Express ∠ F in terms of ∠ G, that is
F = 6G - 2
and since the angles are supplementary, then
G + 6G - 2 = 180, that is
7G - 2 = 180 ( add 2 to both sides )
7G = 182 ( divide both sides by 7 )
G = 26
Thus
∠ G = 26° and ∠ F = 6(26) - 2 = 156 - 2 = 154°
Step-by-step explanation:
x²-3x +5x -15=33
x²-3x+5x=33+15
x²-3x+5x=48
x²+2x=48
divide both sides by 2
x²+x =24
x²= 24
x= ✓24
dunno from here
Answer:
3 1/2
Step-by-step explanation:
5--2=7
6-4=2
7/2= 3 1/2