-2b^2-18b^2 Help me. Plz

2. Describe the transformation of the graph of f(x) = 6* that yields the graph of f(x) = 6*+1

avanturin [10]

Answer: Translation

The difference between the first equation and the second is that the second is moved one space higher. All of its points will be a unit higher than the other. Because of this change in height, the name of the transformation is a translation

Hope this helps comment below for more questions :)

3 0

3 years ago

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

18 values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above 18 values for n are possible.

3 0

2 years ago

3. The photo below is being enlarged to form

Umnica [9.8K]

Answer:

Not enough information

Step-by-step explanation:

Add the photo next time

4 0

2 years ago

If Ryuk eats 7 apples for every 50 names Light writes in the death note, how many apples will he have eaten after Light writes 5

alex41 [277]

Answer:

70 apples

Step-by-step explanation:

We can use a ratio to solve

7 apples x apples

-------------- = -------------

50 name 500 names

Using cross products

7 * 500 = 50x

Divide by 50

7 * 500/50 = 50x/50

70 =x

6 0

2 years ago

Read 2 more answers

Please help!!!!! It's urgent

Evgesh-ka [11]

2b 2a
----------------- + -----------------
(b+a)^2 (b^2 - a^2)

2b 2a
= ----------------- + -------------------
(b+a)(b+a) (b+a)(b-a)

2b(b - a) + 2a(b + a)
= ------------------------------------
   (b+a)(b+a)(b-a)

2b^2 - 2ab + 2ab + 2a^2
= ---------------------------------------
     (b+a)(b+a)(b-a)

2b^2 + 2a^2
= ------------------------
   (b+a)(b+a)(b-a)

2(b^2 + a^2)
= ------------------------
   (b+a)^2 (b-a)

Answer:

Numerator: 2(b^2 + a^2)
Denominator: (b+a)^2 (b-a)

7 0

3 years ago