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Gekata [30.6K]
2 years ago
15

You have been saving $12 each week for many weeks. One day, you decide to count your savings and find that you have $384. Choose

the equations that helps you find how many weeks w you have been saving.
12 384 = w
12 + w = 384
384 - 12 = w
12w = 384
Mathematics
1 answer:
Alex_Xolod [135]2 years ago
4 0

Answer:

D or the last one.

Step-by-step explanation:

Honestly, you got me kinda confused. Is it saying that there is multiple equations to answer this? Well anyways, D would be the answer. When the variable (w) is beside the coefficient, it means you multiple them together. (W) standing for weeks multiplied by 12 which is how much you earn each week would get you the total amount. The rest just don't make sense.

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How do I figure this out?
Ilia_Sergeevich [38]

∠UXW = 36°

∠WZX = 66°

∠UWY = 48°

∠XYZ = 42°


Use the Alternate Exterior Angles Theorem. Always remember that a triangles angles add up 180°, so you can subtract the angles you already know in a triangle to figure out the remaining angle.

8 0
2 years ago
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

3 0
3 years ago
The Gaineys and the Arnolds are saving money for a trip to Utah to go snowboarding. The Arnolds are going to save a nickel on th
Debora [2.8K]

Write a recursive and explicit formula for each option.

  • The Arnolds

Save a nickel on the first day of the month and then double the amount each day for a month

=> a1 =0.05

=> a2 = a1* 2 = 0.05*2

=> a3 = a2*2 = a1* 2*2

..............................................

=>recursive an = a_{n-1} *2

=> explicit an = 0.05*2^{n-1}

  • The Gaineys

Start their savings by saving  $10  on the first day and then  $10  each day of the month

=> a1 = 10

=> a2 = a1 + 10 = 20

=> a3 = a2 +10 = 20 +10 =30

........................................................

=> recursive an = a_{n-1} +10

=> explicit an = 10 + 10( n-1)

Hope it will find you well.

8 0
2 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
Help Please &amp; Thanks
Vanyuwa [196]
I am not sure but I think it’s c
7 0
2 years ago
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