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2 years ago

Can anyone help me in this ???? and tysm !!!

Mathematics

2 answers:

BARSIC [14]2 years ago

6 0

The answer is B. 38 hope this helps

Ilya [14]2 years ago

4 0

Answer:

The answer to the question provided is 38.

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Solve the system of equations - 6x + 8y = –10 and - 4x + y = –11 by combining the equations.

elena55 [62]

Answer: (3, 1) :)

Explanation:
-6x + 8y = -10
-4x + y = -11
-32x + 8y = -88
26x = 78
x = 3
-18 + 8y = -10
8y = 8
y = 1

(Also, can I have brainliest please?)

5 0

2 years ago

WHAT IS -(-2z+5y) HELP MY HOMEWORK IS DUE IN 50 MINUTES PLEASE

vampirchik [111]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{2z - 5y}}}}}$

Step-by-step explanation:

$\sf{ - ( - 2z + 5y)}$

Distribute negative ( - ) sign through the parentheses

$\sf{( - ) \times ( - 2z) + ( - ) \times (5y)}$

$\dashrightarrow{ \sf{2z + ( - 5y)}}$

$\dashrightarrow{ \sf{2z - 5y}}$

Hope I helped!

Best regards! :D

7 0

3 years ago

A person places $686 in an investment account earning an annual rate of 3.8%, compounded continuously. Using the formula V = Pe^

kykrilka [37]

Answer:

V = $1213.03

Step-by-step explanation:

We can determine the amount of money after 15 years with the given formula:

$V = Pe^{rt}$ (1)

Where:

V: is the value of the account in t years =?

P: is the principal initially invested = $686

r: is the rate of interest = 3.8% = 3.8/100 = 0.038

t: is the time = 15 years

By substituting the above values into equation (1) we have:

$V = Pe^{rt} = 686*e^{(0.038*15)} = 1213.03$

Therefore, the amount of money is $1213.03.

I hope it helps you!

6 0

2 years ago

Solve: 3(-x+2) < 15 A X>7 B x < 3 C x<-> D x>-3

sukhopar [10]

Answer:

D x>-3

Step-by-step explanation:

3(-x+2) < 15

-3x + 6< 15 (Subtract 6 from both sides)

-3x < 9 (Divide 3 on both sides)

x>-3 (Flip the inequality because the variable was negative)

7 0

2 years ago

Please explain how - calc ab - see attached photo

baherus [9]

Answer:

Step-by-step explanation:

Set up to different integrals that match the endpoints

so in our case it would look like

$\int\limits^0_{-2} {x} \, dx +\int\limits^1_0 {x+1} \, dx$

now it's just a matter of computing it

$\int\limits^0_{-2} {x} \, dx =x^2\\0^2-(-2)^2=4\\\int\limits^1_0 {x+1} \, dx =\frac{x^2}{2}+x\\\frac{1}{2}+1-0=\frac{3}{2}\\\frac{3}{2}+4=\frac{11}{2}$

4 0

2 years ago