Answer:
A. Clayton could use the relationship (x,y)\rightarrow (y,x)(x,y)→(y,x) to find the points of the image.
C. C’ will remain in the same location as C because it is on the line of reflection.
D. The image and the pre-image will be congruent triangles.
Step-by-step explanation:
A. Clayton could use the relationship (x,y)\rightarrow (y,x)(x,y)→(y,x) to find the points of the image.
This option is TRUE. When we reflect a shape in the line y=xy=x , we just have to swap the x and y coordinates.
B. .Clayton could negate both the x and y values in the points to find the points of the image.
False; This is a rotation of 180\degree180° about the origin.
C. C’ will remain in the same location as C because it is on the line of reflection.
This statement is True
C’ will move because all points move in a reflection.
This statement is false because,C(2,2) and C'(2,2) will have the same coordinate.
D. The image and the pre-image will be congruent triangles.
This is TRUE because reflection is a shape preserving transformation(rigid motion).
E. The image and pre-image will not have the same orientation because reflections flip figures.
This is False
Hope this helps :)
Step-by-step explanation:
