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ale4655 [162]
3 years ago
10

A box contains 10 balls, of which 3 are red, 2 are yellow, and 5 are blue. Five balls are randomly selected with replacement. Ca

lculate the probability that fewer than 2 of the selected balls are red.
Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Answer:

The required probability is 0.1.

Step-by-step explanation:

red balls = 3

yellow balls =  2

blue balls = 5

Selected balls = 5

Number of elemnets in sample space = 10 C 5 = 1260

Ways to choose 1 red ball and 4 other colours =  (3 C 1 ) x (7 C 4) = 105

Ways to choose 5 balls of other colours = 7 C 5 = 21

So, the probability is

\frac{105}{1260} + \frac {21}{1260}\\\\\frac{126}{1260}=0.1  

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