A box contains 10 balls, of which 3 are red, 2 are yellow, and 5 are blue. Five balls are randomly selected with replacement. Ca
lculate the probability that fewer than 2 of the selected balls are red.
1 answer:
Answer:
The required probability is 0.1.
Step-by-step explanation:
red balls = 3
yellow balls = 2
blue balls = 5
Selected balls = 5
Number of elemnets in sample space = 10 C 5 = 1260
Ways to choose 1 red ball and 4 other colours = (3 C 1 ) x (7 C 4) = 105
Ways to choose 5 balls of other colours = 7 C 5 = 21
So, the probability is
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Answer:
the answer is Fife percent. 5%
Step-by-step explanation:
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Answer:
y = 1/2
x = -3/2
Step-by-step explanation:
y = 3x+5
Substance instances of y in the equation.
x + 3x +5 = -1
4x=-6
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Answer:
x = -59/4
Step-by-step explanation:
3 x+ 2 = -x-57
Add x to each side
3 x+x+ 2 = -x+x-57
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Subtract 2 from each side
4x +2-2 = -57-2
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Divide each side by 4
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x = -59/4
Answer:
112
Step-by-step explanation:
