A box contains 10 balls, of which 3 are red, 2 are yellow, and 5 are blue. Five balls are randomly selected with replacement. Ca
1 answer:
Answer:
The required probability is 0.1.
Step-by-step explanation:
red balls = 3
yellow balls = 2
blue balls = 5
Selected balls = 5
Number of elemnets in sample space = 10 C 5 = 1260
Ways to choose 1 red ball and 4 other colours = (3 C 1 ) x (7 C 4) = 105
Ways to choose 5 balls of other colours = 7 C 5 = 21
So, the probability is
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Answer:
The third quartile is 56.45
Step-by-step explanation:
The given parameters are;
The first quartile, Q₁ = 30.8
The median or second quartile, Q₂ = 48.5
The mean, = 42.0
Coefficient of skewness = -0.38
The Bowley's coefficient of skewness (SK) is given as follows;
Plugging in the values, we have;
Which gives;
-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5
11.704 - 0.38·Q₃ = Q₃ - 66.2
1.38·Q₃ = 11.704 + 66.2 = 77.904
Q₃ = 56.45
The third quartile = 56.45.