All categories

3 years ago

Help pls I’ll mark brainliest

Mathematics

1 answer:

Evgen [1.6K]3 years ago

8 0

Answer:

x: 9

EFA: 121

EFC: 70

AFC:131

CFB: 109

I dont know the radius of the circle

AB: 2pi * radius * 22/360

ED: 2pi * radius * 25/360

EAC: 2pi * radius * 290/360

ABC: 2pi * radius * 169/360

DB: 2pi * radius * 180/360

ACE: 2pi * radius *239/360

EBD: 2pi * radius * 335/360

Step-by-step explanation:

x=9, plug and solve from there

You might be interested in

What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in

EastWind [94]

Answer:

$6\sqrt{19} \approx 26.153$ inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment $\mathsf{AG}$ .

In this diagram (not to scale,) $\mathsf{AB} = 26$ (length of prism,) $\mathsf{AC} = 2$ (width of prism,) $\mathsf{AE} = 2$ (height of prism.)

Pythagorean Theorem can help find the length of $\mathsf{AG}$ , one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment $\mathsf{AD}$ . That's the black dotted line in the diagram. In right triangle $\triangle\mathsf{ABD}$ (second diagram,)

Segment $\mathsf{AD}$ is the hypotenuse.
One of the legs of $\triangle\mathsf{ABD}$ is $\mathsf{AB}$ . The length of $\mathsf{AB}$ is $26$ , same as the length of this prism.
Segment $\mathsf{BD}$ is the other leg of this triangle. The length of $\mathsf{BD}$ is $2$ , same as the width of this prism.

Apply the Pythagorean Theorem to right triangle $\triangle\mathsf{ABD}$ to find the length of $\mathsf{AB}$ , the hypotenuse of this triangle:

$\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}$ .

Consider right triangle $\triangle \mathsf{ADG}$ (third diagram.) In this triangle,

Segment $\mathsf{AG}$ is the hypotenuse, while
$\mathsf{AD}$ and $\mathsf{DG}$ are the two legs.

$\mathsf{AD} = \sqrt{26^2 + 2^2}$ . The length of segment $\mathsf{DG}$ is the same as the height of the rectangular prism, $2$ (inches.) Apply the Pythagorean Theorem to right triangle $\triangle \mathsf{ADG}$ to find the length of the hypotenuse $\mathsf{AG}$ :

$\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}$ .

Hence, the length of the longest line segment in this prism is $6\sqrt{19} \approx 26.153$ inches.

5 0

3 years ago

What’s the slope between (4,5) and (1,2)

choli [55]

Your answer would be 1

5 0

3 years ago

Find the product -12 • (-2) A. 10 B. 24 C. -24 D. -14

svetoff [14.1K]

12 x 2 = 24

When you multiply two negative numbers, the answer will be a positive
When you multiply one negative and one positive, the answer will be negative.

Using that rule:

(-12)(-2) = 24

24 is your answer

hope this helps

6 0

3 years ago

Which one is it........

ruslelena [56]

$\begin{cases}4(x+y)=2x+12\\4x+y=x+8\end{cases}\\\\\\
\begin{cases}4x+4y=2x+12\quad|-2x\\4x+y=x+8\quad|-x\end{cases}\\\\\\
\begin{cases}4x+4y-2x=12\\4x+y-x=8\end{cases}\\\\\\
\boxed{\begin{cases}2x+4y=12\\3x+y=8\end{cases}}$

3 0

3 years ago

Using this number cube and spinner, which simulation would help you answer this question?

Katen [24]

Probability: Probability of an event to occur is given by:

Probability of Wednesday:

Probability of first day rainy:

Probability that first day is rainy Wednesday:
Let probability
Since these two events are independent

Percentage chances of rainy Wednesday

4 0

3 years ago