Answer:
23.6 mmHg.
Explanation:
From the question given above, the following data were obtained:
Total pressure (Pₜ) = 760.0 mmHg.
Pressure of nitrogen (Pₙ) = 585.2 mmHg
Pressure of oxygen (Pₒ) = 144.4 mmHg,
Pressure of argon (Pₐ) = 6.8 mmHg.
Pressure of water vapor (Pᵥ) =?
The pressure exerted by the water vapor can be obtained as follow:
Pₜ = Pₙ + Pₒ + Pₐ + Pᵥ
760 = 585.2 + 144.4 + 6.8 + Pᵥ
760 = 736.4 + Pᵥ
Collect like terms
760 – 736.4 = Pᵥ
23.6 = Pᵥ
Pᵥ = 23.6 mmHg
Thus, the pressure exerted by the water vapor is 23.6 mmHg
