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AlexFokin [52]
2 years ago
7

Using the given table of an exponential function, determine the growth/decay factor as well as the rate of increase/decrease. Ty

pe your answers in as numbers. Example: Growth Factor: 3.5, Rate of Increase: 2.5. (Do not input your rate of increase as a percent.)
f(x)=75(1-.3)^x
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
4 0

Answer:

0.7 is the growth factor

0.3 is the growth rate

Step-by-step explanation:

Here, we want to get the growth rate and the growth factor

Let us consider the general form of an exponential equation

That will be;

y = a(1 + r)^n

The growth rate is r

while the growth factor is the term (1 + r)

From the given exponential function;

-0.3 is the rate of increase

Growth rate is 1-0.3 = 0.7

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What positive number is left of 1 ( 0 is neutral)
kkurt [141]

Answer:

any number between 0 and 1

Step-by-step explanation:

This includes decimals.

8 0
2 years ago
The time, T (seconds) it takes for a pot of water to boil is inversely proportional to the cooker setting, H, applied to the pot
kherson [118]

Answer:

200

Step-by-step explanation:

T = x * (1/H)

x = T*H

x = 2800

so for H = 14

T = 2800 * (1/14) = 200

7 0
3 years ago
If the demand function for a commodity is given by the equation
Margarita [4]

Answer:

Equilibrium quantity = 26.92

Equilibrium price is $31.13

Step-by-step explanation:

Given :Demand function : p^2 + 16q = 1400

           Supply function : 700 -p^2 + 10q = 0

To Find : find the equilibrium quantity and equilibrium price.

Solution:

Demand function : p^2 + 16q = 1400  --A

Supply function : p^2-10q=700 ---B

Now to find the equilibrium quantity and equilibrium price.

Solve A and B

Subtract B from A

p^2-10q -p^2-16q=700-1400

-26q=-700

26q=700

q=\frac{700}{26}

q=26.92

So, equilibrium quantity = 26.92

Substitute the value of q in A

p^2 + 16(26.92) = 1400

p^2 + 430.72 = 1400

p^2 = 1400- 430.72

p^2 = 969.28

p = \sqrt{969.28}

p = 31.13

So, equilibrium price is $31.13

7 0
3 years ago
Approximately how many kcal are contained in 3 ounces of 80-proof rum?
Mekhanik [1.2K]
3 ounces of 80-proof rum approximately contains 200,000 cal.

Now, we need to convert the cal into kcal. We know that:
1 cal = 1000 kcal
Therefore,
200,000 cal = 200 kcal
4 0
2 years ago
Mr. Mace's class is planning a field trip, and 3/5 of his students want to go to Chicago. Of those who want to go to Chicago, 2/
MrMuchimi
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2 years ago
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