The answer of the question is 5 beaches 4x-5’7 and when you put the power to 100
Answer:
The anchor should be located at the midpoint between the 20m high and 60m high antennas.
Step-by-step explanation:
Let the length of cable for 20m high antenna be represented by x, and that for 60m high antenna be y.
The single length of cable required = x + y.
From the principle of geometry, if the cable is anchored at 200m from the 20m high antenna, it forms a right angled triangle. Applying the Pythagoras theorem,
x =
= 199
Applying the same principle to the 60m high antenna gives,
y =
= 191
The single length of cable required = 199+ 191
= 390m
Varying the point of location of the anchor between the two antennas causes an increase in the length of cable required.
The anchor should be located at the midpoint between the two antennas to achieve a minimum amount of cable.
Can you give me any options for this question
Answer:
15%
Step-by-step explanation:
Before a sale, an item’s price was $38.00.
Original price, p = $38.00
After the sale discount, the price became $32.30.
After discount price, q = $32.30
Difference of sale = 38.00 - 32.30
= $5.70
% of sale distance
Hence, The sale discount is 15%
2r + 2r + 5 + r + 4r - 3 = 38
9r + 5 - 3 = 38
9r + 2 = 38
9r = 38 - 2
9r = 36
9r/9 = 36/9
r = 4cm
Done!