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wariber [46]
3 years ago
7

How does negative feedback influence the behavior of a system?

Engineering
2 answers:
liberstina [14]3 years ago
7 0

Answer:

Negative feedback affects the behavior of a system in the sense that control elements reverse the process' direction by changing input conditions so that output can be set at a desired condition to meet safety, quality, and cost-worthiness requirements.

Explanation:

If this helps you please mark brainliest!

Have a nice day!

12345 [234]3 years ago
5 0

Answer:

Explanation:

A negative feedback influences the behavior of a system (i.e. a process) in the sense that control elements (controller) reverse the direction of the process by changing input conditions (action component) so that output can be set at a desired condition in order to fulfill safety, quality and cost-worthiness

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For the SR-latch below high levels of Set and Reset result in Q= 1 and 0, respectively. The next state is unknown when both inpu
dusya [7]

Answer:

hello your question lacks the required image attached to this answer is the image required

answer :  NOR1(q_) wave is complementary to NOR2(q)

Explanation:

Note ; NOR 2 will be addressed as q in the course of this solution while NOR 1 will be addressed as q_

Initial state is unknown i.e q = 0 and q_= 1

from the diagram the waveform reset and set

= from 0ns to 20ns reset=1 and set=0.from the truth table considering this given condition q=0 and q_bar=1 while  

from 30ns to 50ns reset=0 and set=1.from the truth table considering this condition q=1 and q_bar=1.so from 35ns also note there is a delay of 5 ns for the NOR gate hence the NOR 2 will be higher ( 1 )

From 50ns to 65ns both set and reset is 0.so NOR2(q)=0.

From 65 to 75 set=1 and reset=0,so our NOR 2(q)=1 checking from the truth table

also  from 75 to 90 set=1 and reset=1 , NOR2(q) is undefined "?" and is mentioned up to 95ns.

since q_ is a complement of q, then NOR1(q_) wave is complementary to NOR2(q)

3 0
3 years ago
Calculate the wire pressure for a round copper bar with an original cross-sectional area of 12.56 mm2 to a 30% reduction of area
dybincka [34]

Answer:153.76 MPa

Explanation:

Initial Area\left ( A_0\right )=12.56 mm^2

Final Area\left ( A_f\right )=0.7\times 12.56 mm^2=8.792 mm^2

Die angle=30^{\circ}

\alpha =\frac{30}{2}=15^{\circ}

\mu =0.08

Yield stress\left ( \sigma _y \right )=350 MPa

B=\mu cot\left ( \aplha\right )=0.2985

\sigma _{pressure}=\sigma _y\left [\frac{1+B}{B}\right ]\left [ 1-\frac{A_f}{A_0}\right ]^B

\sigma _{pressure}=350\left [\frac{1+0.2985}{0.2985}\right ]\left [ 1-\frac{8.792}{12.56}\right ]^{0.2985}

\sigma _{pressure}=153.76 MPa

8 0
3 years ago
What are the advantages of triggering circuit<br> for thyrestors?
sergejj [24]

Answer:

For most applications, it is simple, dependable, efficient, and straightforward to apply - a simple trigger signal may be provided, with appropriate processing if necessary. This implies that an appropriate trigger signal may be generated using other electrical circuits and then applied to the SCR.

Explanation:

3 0
3 years ago
The depletion in the Ozone layer is caused by:
andrew11 [14]
D. Chlorofluorocarbon

This is a man-made carbon that causes the gradual thinning(deception) in the earth’s Ozone layer.

Hope this helped and pls mark as brainliest!

~ Luna
3 0
3 years ago
Read 2 more answers
Why can you anodise Aluminium and Magnesium alloys?
Anastasy [175]

Explanation:

Anodizing :

 Anodizing is the surface protection process from the environment.As we know that due to external environment surfaces get corrodes .By using anodizing process the outer surface  of material coated by using different type of coating material.

As the name stand that in the anodizing process there will be anode and oxygen.in this process oxidation of material take place .

Oxides of aluminium and magnesium are stable that is why they anodized by this process.

4 0
4 years ago
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