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Natasha2012 [34]
2 years ago
7

Multiple Choice

Engineering
1 answer:
hichkok12 [17]2 years ago
4 0

Answer:

Geological engineers can help determine if the soil and structural stability in the building's location are satisfactory.

Explanation:

Geologic Engineering refers to a job which applies<em> geology to engineering</em>. This type of job focuses on the investigation of sites in response to<em> soil, rock </em>and <em>groundwater.</em> They help design the major structures for engineering works, thus, it is also their role <u><em>to know whether the building's soil and structural stability are satisfactory.</em></u> They determine <em>how much of the structure is a safe load for the soil it is standing upon.</em> They also test the strength of both rock and soil at different depths. This will help them know whether the location will be suitable for the skyscraper.

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Conclude from the scenario below which type of documentation Holly should use, and explain why this would be the best choice. Ho
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Answer:

Okay

Explanation:

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3 years ago
If a system of pulleys results in a force of 25% of the load, how far will the rope need to move to pull the load a distance of
GaryK [48]

Answer:

  40 ft

Explanation:

Assuming no loss of energy in the system of pulleys, the work done is the same whether you move the load directly or through the pulleys.

  W = Fd . . . . . . . . work is the product of force and distance

  F(10 ft) = (0.25F)(d) . . . . . where d is the distance we want to find

  d = 10F/(0.25F) = 40

The rope will need to move 40 feet.

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2 years ago
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Vedmedyk [2.9K]

Answer:

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Explanation:

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3 0
3 years ago
Read 2 more answers
(1) Prompt the user for the number of cups of lemon juice, water, and agave nectar needed to make lemonade. Prompt the user to s
Lady bird [3.3K]

Answer:

The program to this question as follows:

Program:

Lemon= float(input('Enter lemon juice value in cups: ')) #defining float variable and input value by user

Water= float(input('Enter water value in cups: ')) #defining float variable and input value by user

Agave= float(input('Enter agave nectar value in cups: ')) #defining float variable and input value by user

Serve= float(input('enter serving value: '))  #defining float variable and input value by user

print ('Lemonade ingredients - yields',Serve,'servings',) #print value

print (Lemon,'cups in lemon juice',) #print value

print (Water,'cups in water',) #print value

print (Agave,'cups in agave nectar',) #print value

Output:

Enter lemon juice value in cups: 2

Enter water value in cups: 3

Enter agave nectar value in cups: 2

enter serving value: 2

Lemonade ingredients - yields 2.0 servings

2.0 cups in lemon juice

3.0 cups in water

2.0 cups in agave nectar

Explanation:

In the above python code, four float variable "Lemon, Water, Agave, and Serve" is defined, which is the input function is used.  

  • The input function message is written that passes in function parameter, that accepts value in the above variables.  
  • In the next step, the print function is used, which prints the above user input values.
6 0
3 years ago
he mean weight of a breed of yearling cattle is 11871187 pounds. Suppose that weights of all such animals can be described by th
Tamiku [17]

Question

The mean weight of a breed of yearling cattle is 1187 pounds. Suppose that weights of all such animals can be described by the Normal model ​N(1187,78). ​

a) How many standard deviations from the mean would a steer weighing 1000 pounds​ be?

b) Which would be more​ unusual, a steer weighing 1000 ​pounds, or one weighing 1250 ​pounds? ​

Answer:

a. z = -2.40

A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.

b. z = 0.81

1000 is more unusual because its contained on the extreme end from the mean

Explanation:

a.

Let weight (in pounds) of the cattle be denoted by letter x:

z = (x - u)/ σ

Where u = mean and σ = standard deviation

u = 1187

σ = 78

x = 1000

Use z score formula to standardize the value of x:

z = (1000 - 1187)/78

z = -187/78

z = -2.397436

z = -2.40 ------_ Approximated

A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.

b.

x= 1250

z= (1250 - 1187)/78

z = 63/78

z = 0.807692

z = 0.81 --------- Approximated

1000 is more unusual because its contained on the extreme end from the mean

8 0
3 years ago
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