All categories

2 years ago

Multiple Choice

Engineering

1 answer:

hichkok12 [17]2 years ago

4 0

Answer:

Geological engineers can help determine if the soil and structural stability in the building's location are satisfactory.

Explanation:

Geologic Engineering refers to a job which applies geology to engineering. This type of job focuses on the investigation of sites in response to soil, rock and groundwater. They help design the major structures for engineering works, thus, it is also their role to know whether the building's soil and structural stability are satisfactory. They determine how much of the structure is a safe load for the soil it is standing upon. They also test the strength of both rock and soil at different depths. This will help them know whether the location will be suitable for the skyscraper.

You might be interested in

Who is the mystical body of Christ

Sergeu [11.5K]

If you're talking ab jesus christ , some religions believe it was god in human form and some believe it was gods son it all depends on the religion and how it's taught

8 0

2 years ago

Read 2 more answers

What are the causes and solutions of social problems ?what are the causes and solutions of social problems

aksik [14]

Answer:

causes: unemployment, poverty,Lack of education,urbanization e.t.c

solutions:making people educated, giving people jobs

7 0

2 years ago

Write 3 classes with three levels of hierarchy: Base, Derive (child of base), and D1 (child of Derive class). Within each class,

PIT_PIT [208]

Answer:

class Base

{

void m1()

{

System.out.println("Origin: Base Class");

}

class Derive extends Base

{

void m1()

{

System.out.println("Origin: Derived Class");

}

class D1 extends Derive

{

void m1()

{

System.out.println("Origin: D1 - Child of Derive Class");

}

class TestDynamicBinding

{

public static void main(String args[])

{

Base base = new Base(); // object of Base class

Derive derive = new Derive(); // object of Derive class

D1 d1 = new D1(); // object of D1 class

Base reference; // Reference of type Base

reference = base; // reference referring to the object of Base class

reference.m1(); //call made to Base Class m1 method

reference = derive; // reference referring to the object of Derive class

reference.m1(); //call made to Derive Class m1 method

reference = d1; // reference referring to the object of D1 class

reference.m1(); //call made to D1 Class m1 method

}

Explanation:

The solution demonstrates dynamic binding behavior because the linking procedure used calls overwritten method m1() is made at run time rather than doing it at the compile time. The code to be executed for this specific procedural call is also known at run time only.

6 0

3 years ago

Can someone help me plz!!! It’s 23 points

Marina86 [1]

Answer:

0.00695 A

Explanation:

µ represents $10^{-6}$ . Multiply this by 6,950.

5 0

2 years ago

Link BD consists of a single bar 36 mm wide and 18 mm thick. Knowing that each pin has a 12-mm diameter, determine the maximum v

MAXImum [283]

Answer:

hello the diagram attached to your question is missing attached below is the missing diagram

answer :

a) 48.11 MPa

b) - 55.55 MPa

Explanation:

First we consider the equilibrium moments about point A

∑ Ma = 0

( Fbd * 300cos30° ) + ( 24sin∅ * 450cos30° ) - ( 24cos∅ * 450sin30° ) = 0

therefore ; Fbd = 36 ( cos ∅tan30° - sin∅ ) kN ----- ( 1 )

A ) when ∅ = 0

Fbd = 20.7846 kN

link BD will be under tension when ∅ = 0, hence we will calculate the loading area using this equation

A = ( b - d ) t

b = 12 mm

d = 36 mm

t = 18

therefore loading area ( A ) = 432 mm^2

determine the maximum value of average normal stress in link BD using the relation below

бbd = $\frac{Fbd}{A}$ = 20.7846 kN / 432 mm^2 = 48.11 MPa

b) when ∅ = 90°

Fbd = -36 kN

the negativity indicate that the loading direction is in contrast to the assumed direction of loading

There is compression in link BD

next we have to calculate the loading area using this equation ;

A = b * t

b = 36mm

t = 18mm

hence loading area = 36 * 18 = 648 mm^2

determine the maximum value of average normal stress in link BD using the relation below

бbd = $\frac{Fbd}{A}$ = -36 kN / 648mm^2 = -55.55 MPa

4 0

2 years ago