Answer:
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Answer:
≈ 53 seconds
Explanation:
<u>calculate Time required for the product to begin the falling-rate drying period</u>
Initial moisture content = 0.77 kg water /kg of product
= 3.35 kg water /kg solids
Critical moisture content = 0.3 kg water / kg product
= 0.43 kg water / kg solids
∴ amount of water to be removed = 3.35 - 0.43 = 2.95kg water /kg solids
next: calculate surface are a of product during drying
= (0.05 * 0.05 ) * 6
= 0.015 m^3
Drying rate = 0.1 kg water m^2.s^-1 * 0.015 m^3 = 1.5 * 10^-3 kg water s^-1
<em>applying product density</em>
initial product mass = 0.11875 * 0.23 = 0.0273kg solid
hence total amount of water to removed = 2.92 * 0.0273 = 0.07972 kg
therefore : <u>T</u><em>ime required for the product to begin the falling-rate drying period</em>
= 0.07972 / 1.5 * 10^-3
= 53 seconds
Answer:
The effective overall heat transfer coefficient for the combination,
Explanation:
According to the question, the total area includes the areas of the wall, window and door.
Total area, A = 100 * 10 = 1000 ft²
Area of the window,
Area of the door,
Area of the wall,
<u>Heat transfer coefficients:</u>
For wall,
For window,
For door,
To get the overall heat - transfer coefficient for the combination: