Answer:
HEAT LOST
polycarbonate = 252 W
soda lime glass = 1680 W
aerogel = 16.8 W
COST associated with heat loss
polycarbonate = $ 262.08
soda lime glass = $ 1,747.2
aerogel = $ 17.472
The cost associated with heat loss is maximum in Soda Lime and minimum in Aerogel
Explanation:
Given that;
surface area for each window = 0.4m * 0.4m = 0.16m^2
DeltaT = 90°C, L = 12mm = 0.012m
thermal conductivity of soda line can be gotten from tables in FUNDAMENTALS OF HEAT AND MASS TRANSFER
so at 300K
KsL = 1.4 W/mK
Kag = 0.014 W/mK
Kpc = 0.21 W/mK
Now HEAT LOSS
for polycarbonate;
Qpc = -KA dt/dx
NOTE ( heat flows from high temperature region to low temperature regions. so the second temperature would be smaller compared to the initial causing a negative in the change in temperature)
so Qag = (0.21 * 0.16 * 90) / 0.012
= 252 W
for soda lime glass;
Qsl = (1.4 * 0.16 * 90) / 0.012
= 1680 W
for aerogel
Qaq = (0.014 * 0.16 * 90) / 0.012
= 16.8 W
Now for COST associated with heat lost
for polycarbonate;
cost = Qpc * 130 * 8 * 1/1000
= 252 * 130 * 8 * 1/1000
= $ 262.08
for soda lime glass;
cost = 1680 * 130 * 8 * 1/1000
= $ 1,747.2
for aerogel
cost = 16.8 * 130 * 8 * 1/1000
= $ 17.472
Therefore the cost associated with heat loss is maximum in Soda Lime and minimum in Aerogel
