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2 years ago

Select all ratios equivalent to 2:6. A. 6:2 B.27:9 C.16:48

Mathematics

1 answer:

AlladinOne [14]2 years ago

6 0

Answer:

Step-by-step explanation:

since after you simplify c u end up with 2:6

Choice C

16:48

divide by 2

8:24

divide by 2

4:12

divide by 2

2:6

choice A

6:2

divide by 2

3:1

Choice B

27:9

divide by three

9:3

divide by three

3:1

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Jill has $1.25 in her pocket. The money is in quarters and dimes. There are a total of 8 coins. How many quarters and dimes does

erica [24]

Answer:

3 quarters
5 dimes

Step-by-step explanation:

Let q represent the number of quarters (the higher-value coin). Then 8-q is the number of dimes, and Jill's total amount in change is ...

0.25q +0.10(8-q) = 1.25

0.15q + 0.80 = 1.25 . . . . . . . eliminate parentheses

0.15q = 0.45 . . . . . . . . . . . . . subtract 0.80

q = 3 . . . . . . . . . . . . . . . . . . . . divide by 0.15

the number of dimes is 8-q = 8-3 = 5.

Jill has 3 quarters and 5 dimes.

5 0

3 years ago

Read 2 more answers

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$