Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
C
Step-by-step explanation:
The equation in slope-intercept is y=0.625x+7.
y = mx + b
where:
m is the slope of the line
b is the y-intercept of the line
The slope m of the line through any two points (x1, y1) and (x2, y2) is given by:
The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x1, y1) we have y1 = mx1 + b, the y-intercept b can be calculated by:
b = y1 - mx<span>1. hope that helped</span>
9514 1404 393
Answer:
- 14/9
- -3.6
- 5/4
- 11/2, 7/8, 5/18
Step-by-step explanation:
1. n = (11/6 -2/3)(4/3) = (7/6)(4/3) = 14/9
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2. x = (9.82 -28.18)/5.1 = -3.6
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3. y = 3/2 -1/4 = 5/4
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4a. t = 2(3 -1/4) = 11/2
4b. y = (1/5 +1/2)(5/4) = ((2+5)/10)(5/4) = 7/8
4c. x = (11/3 -2)/6 = (5/3)(1/6) = 5/18
