For finding the perimeter of abc (triangle), we MUST need the two others coordinates of b and c
let b(1, 2) and c (2, -4)
we need to calculate the distances ab, ac, and bc
vector (ab)=(1-(-2), 2-9)=(3, -7), so its length is ab=sqrt(3²+ (-7)²)=7.61
realising the same method, we find bc=6.08, ac=13.60
so the perimeter of abc is P= ab+bc+ca=13.60+6.08+7.61=27.29
K^2 +3k +5k + 15
k (k+3) +5 (k+3)
(k+5)(k+3)
So, the correct option is the last one.
Answer:5.4 km
Step-by-step explanation:
Answer:
C. 6
Step-by-step explanation:
Looking at the value of AC, you can assume that it is the same value as CD because it is divided in the middle with a 90-degree angle in which it is 12. Assuming that the line BF is also divided in half, you should divide 12 by 2 in which you get the final answer as 6.