Answer:
The answer is Discrete Random Variable
Step-by-step explanation:
A random variable is considered discrete if its possible values are countable.
In our case,
In a basketball game, for example, it is only possible for a team's score to be a whole number—no fractions or decimals are allowed, and so the score is discrete.
A good rule of thumb is this: if the variable you're measuring has to be rounded before it's written down, then it's continuous. If no rounding is necessary, as with anything that's countable, then it's discrete.
angle 1 = 180° - 115° (Linear Pair)
<u>angle 1 = 65°</u>
<u>angle 2 = angle 1 = 65°</u> ( Angles on the equal sides of an isosceles triangle )
angle 3 = 180° - (65° + 65°) (Angle Sum Property)
angle 3 = 180° - 130°
<u>angle</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>5</u><u>0</u><u>°</u>
angle 4 = 180° - 65° (Linear Pair)
<u>angle</u><u> </u><u>4</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u>
<u>angle</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u> (Vertically Opposite Angles)
Answer:
Solution of the system of equations: (1, 1)
x = 1, y = 1
Explanation:
Given the below system of equations;

Note that the slope-intercept form of the equation of a line is given as;

where m = slope of the line
b = y-intercept of the line
Comparing the given system of equations with the slope-intercept equation, we can see that, for the 1st equation (y = -3x + 4), the slope(m) = -3 and y-intercept(b) = 4 and for the 2nd equation, slope(m) = 3 and y-intercept(b) = -2.
Knowing the above information, let's go ahead and graph the system of equations;
From the above graph, the point of intersection of the two lines (1, 1) is the solution of the system of equation.
C. p-125
The original price minus the sale
A(-8,0) B(-12,12)the center is w((-8-12)/2 , (0+12)/2)....(midel [ AB]w(-10 ,6)the ridus is : r = AB/2AB = √(-12+8)²+(12-0)² = √16+144 =√160/2an equation in standard form equation of the circle :(x+10)²+(y-6)² = (√160/2)²=160/4 = 40