Busco novia lesbiana mi inta es Arianaprince1

2. In the equation 5(x - 3) = 25, what should you do after using the Distributive Property?

son4ous [18]

Answer:

umm... This how I learned from the chapter simple equation. Hopefully helps

Step-by-step explanation:

5(x - 3) = 25 we have to find the value of 'x'

so transpose 5 x to the other side = (x - 3) = 25 divided by 5 becuz it was multiplication on the other side so it is equal to = (x - 3) = 5

Now we transpose -3 which is equal to = x = 5 + 3 = 8

so, x = 8

hopefully it helps!!!!!!!

7 0

3 years ago

Read 2 more answers

Tawny has 2 1/2 pints of juice. She has glasses that can hold 5 fluid ounces. How any glasses can she fill with juice?

Oduvanchick [21]

1 pint = 20 fl. oz
20/5 = 4 cups can be filler per pint
4*2.5 = 10 cups can be filled overall

6 0

3 years ago

Bernadette bought two pieces of ribbon. One piece is 6 1/4 feet long and the other 11 1/2 whats the total length

Yuki888 [10]

The answer would be, 17 3/4

5 0

3 years ago

Read 2 more answers

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

i)

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

3 years ago

4. What value of x makes the inequality true? 3(2x - 1) - 11x S -3x + 5

NNADVOKAT [17]

Answer:

A. {x: x ≥ -4}

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
{Builder Set Notation}

Step-by-step explanation:

Step 1: Define

Identify

3(2x - 1) - 11x ≤ -3x + 5

Step 2: Solve for x

[Distributive Property Distribute 3: 6x - 3 - 11x ≤ -3x + 5
[Subtraction] Combine like terms: -5x - 3 ≤ -3x + 5
[Addition Property of Equality] Add 5x on both sides: -3 ≤ 2x + 5
[Subtraction Property of Equality] Subtract 5 on both sides: -8 ≤ 2x
[Division Property of Equality] Divide 2 on both sides: -4 ≤ x
Rewrite: x ≥ -4

6 0

3 years ago