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prisoha [69]
3 years ago
14

Find the missing terms 14.5_,_,18.4

Mathematics
2 answers:
Gelneren [198K]3 years ago
8 0

Answer:

16.6

Step-by-step explanation:

kifflom [539]3 years ago
4 0
The first term is a which is equal to 14.5

The 4th term is a + 3d = 18.4

We know what a is so we can substitute it into the above equation...

14.5 + 3d = 18.4

3d = 3.9

d = 1.3

So the common difference is 1.3... now you just have to add that to the first term so...

14.5 + 1.3 = 15.8 (2nd term)

15.8 + 1.3 = 17.1 (3rd term)

Hope this helps! Any questions let me know:)

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3 years ago
Identify the slope and y-intercept of this equation and then show the steps to convert to standard form
kirill [66]

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5 0
3 years ago
the third term of an arithmetic sequence is 24 and the fifth is 32 if the first term is a1. which is an equation nth term of the
const2013 [10]
An = a1 + (n - 1)(d)
Where a1 is the first term and d is the common difference.
First find d, the common difference.
24, ____, 32
a3 a4 a5
Subtract 32-24 = 8
Subtract a5 - a3 = 2
Divide 8/2 = 4
d = 4
Use d and one of the values they give us to find a1.
a3 = 24
24 = a1 + (3 - 1)(4)
24 = a1 + 2(4)
24 = a1 + 8
Subtract 8 from both sides
16 = a1
an = 16 + (n - 1)(4)
Can also be written
an = 16 + 4n - 4
an = 4n + 12
8 0
3 years ago
Read 2 more answers
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