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igomit [66]
3 years ago
5

According to the sequence of numbers, find the exponential function.

Mathematics
1 answer:
Vikki [24]3 years ago
4 0
The answer to this is 3
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Given f(x)=70+11x, find x when f(x)=158 <br> A.8<br> B.7<br> C.1738<br> D.88
Ray Of Light [21]
I got 1808 is your multiple choice wrong?
5 0
4 years ago
Jerry has 6 candys he lost 2 how much does he have?
Aleksandr-060686 [28]

Answer:

Hello there!

Since he had 6 candies and lost two, all you have to do is subtract 2 from 6.

Therefore, Jerry only has 4 candies.

Hope this helps!!!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Jenny's bakery sells carrot muffins at 2 dollars each. The electricity to run the over is over 120 dollars per day and the cost
g100num [7]

Answer:

200 muffins

Step-by-step explanation:

The selling price of each muffin = $2

The cost price of each muffin = $1.40

The price of electricity = $120

If the number of muffins that Jenny sells in a day is x, then, Jenny's total cost in a day is:

120 + (1.4 * x) = 120 + 1.4x

and the total sales earnings in a day for x muffins will be:

2 * x = 2x

To break even, the total costs in a day must equal to the total earnings. That is;

2x =  120 + 1.4x

Solving this:

2x - 1.4x = 120\\\\\\0.6x = 120\\\\\\x = 120/0.6\\\\\\x = 200

She must sell 200 muffins in a day to break even.

7 0
3 years ago
PLEASE HELP ME ASAP I REALLY NEED HELP!!!
padilas [110]

1) \overline{UP}

2) \overline{UP} \cong \overline{UP}

3) \overline{UR}

4) \overline{PR}

5) \triangle OUP \cong \triangle RUP by SSS

6) CPCTC

7 0
2 years ago
A random sample of 49 statistics examinations was taken. the average score, in the sample, was 84 with a variance of 12.25. the
tester [92]

Since in this case we are only using the variance of the sample and not the variance of the real population, therefore we use the t statistic. The formula for the confidence interval is:

<span>CI = X ± t * s / sqrt(n)                      ---> 1</span>

Where,

X = the sample mean = 84

t = the t score which is obtained in the standard distribution tables at 95% confidence level

s = sample variance = 12.25

n = number of samples = 49

From the table at 95% confidence interval and degrees of freedom of 48 (DOF = n -1), the value of t is around:

t = 1.68

 

Therefore substituting the given values to equation 1:

CI = 84 ± 1.68 * 12.25 / sqrt(49)

CI = 84 ± 2.94

CI = 81.06, 86.94

 

<span>Therefore at 95% confidence level, the scores is from 81 to 87.</span>

6 0
4 years ago
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