3 years ago

What is the area of the circle shown? Use 3.14 for pi.

Mathematics

1 answer:

den301095 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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Given a = -3, b=4 and c= -5, evaluate a + b + c. 04 0-6 -12

Rainbow [258]

Answer: 0 - 4

Step-by-step explanation:

0 - 4 = -4

-3 + 4 = 1

1 - 5 = -4

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3 years ago

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where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

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An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.

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Step-by-step explanation:

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3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

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4 years ago

if all of the medians of a triangle were constructed, what would the point where they all intersect be called?

Lubov Fominskaja [6]

Answer:

i think its centroid not sure though.

Step-by-step explanation:

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4 years ago