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Y_Kistochka [10]
3 years ago
12

PLEASE HELP DUE BY MIDNIGHT ILL GIVE YOU BRAINLINEST and 17 POINTS

Mathematics
1 answer:
Leto [7]3 years ago
3 0
Answer:
1). 40ft^2
2). 32.1 cm^2
3). 28 in^2
4). 44 cm^2
5). 148.8m^2
6). 110.7 cm^2

Explanation:
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A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
Herr is the question and pic for the last question its 2
nevsk [136]
To find the area of the triangle you would have to plug in the numbers for this equation: A= Hxb/2
So in your case 14x10/2
140/2= 70 and that would be your answer. Answer:G
3 0
3 years ago
Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d
Olegator [25]

Answer:

The speed of the cars is 32 \frac{km}{h}

Step-by-step explanation:

First we must first have the clear concept that speed=\frac{distance}{time} or s=\frac{d}{t}

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: s_{1}=s+1 , t_{1}=2 and d_{1}= d_{2}

Car 1: s_{2}=s-10 , t_{2}=3 and d_{1}= d_{2}

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

d_{1}=s_{1}*t_{1}

d_{1}=(s+1)*2

d_{1}=2s+2

<em>Car 2</em>

d_{2}=s_{2}*t_{2}

d_{2}=(s-10)*3

d_{2}=3s.30

d_{1}=d_{2}

2s+2=3s-30

2+30=3s-2s

32=s

The speed of the cars is 32 km/hr

7 0
3 years ago
The length of Rectangle A is 20 inches and the width is 4 inches. The length of Rectangle B is
astraxan [27]

Answer:

8 inches

Step-by-step explanation:

Let w be the width of rectangle B.

Since, both rectangles are similar.

Therefore, corresponding lengths and widths of rectangles A and B will be in proportion.

\therefore \frac{20}{40}  =  \frac{4}{w}  \\  \\  \frac{1}{2}  =  \frac{4}{w}  \\  \\ w = 2 \times 4 \\  \\ w = 8 \: inches

5 0
3 years ago
Read 2 more answers
How do I study for a big math test? any tips on how to study I'm a visual learner.
Nastasia [14]

Honestly? Just review your notes and try to work out the problems yourself before taking a look at the answer. You can also google specific topics that the test will cover and try the practice problems.

3 0
3 years ago
Read 2 more answers
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