Question

An airplane is observed to be approaching the air point. It is at a distance of 12 km from the point of observation and makes an

Answer 1

Answer:

The height is 14.3 km

Step-by-step explanation:

Given

$distance= 12km$

$\theta= 50$ --- angle of elevation

Required

Determine the height above the ground

The question is illustrated using the attached image.

To calculate the required height, we make use of:

$tan(\theta) = \frac{AB}{BC}$

Where AB represents the height and BC, the distance.

So:

$tan(50) = \frac{AB}{12}$

Make AB the subject

$AB = 12 * tan(50)$

$AB = 12 * 1.1918$

$AB = 14.3016$

$AB = 14.3km$ --- approximated