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3 years ago

Hello please help i’ll give brainliest

Mathematics

1 answer:

poizon [28]3 years ago

6 0

Answer:

an organism killing another organism for food

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X=-y+3 <br> 3y+x=5 pleaasseee heellppp meee

love history [14]

3y+(-y+3)=5
2y+3=5
2y=2
y=1
x=-(1)+3
x=2
Your answer is (2,1)
Hope this helps

6 0

2 years ago

Read 2 more answers

The data reflects the number of days since a plant has

AURORKA [14]

Answer:

I think its b. Every 0.81 days the plant grows 0.07 inches.

Step-by-step explanation:

i took the same test on egd.

5 0

2 years ago

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

zaharov [31]

After 6 years the investment is $5555.88

Step-by-step explanation:

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

The formula used to find future value is:

$A(t)=P(1+\frac{r}{n})^{nt}$

where A(t) = Accumulated amount

P = Principal Amount

r = annual rate

t= time

n= compounding periods per year

We are given:

P = $3600

r = 7.5 %

t = 6

n = 1

Putting values in formula:

$A(t)=P(1+\frac{r}{n})^{nt}\\A(t)=3600(1+\frac{0.075}{1})^{6*1}\\A(t)=3600(\frac{1.075}{1})^6\\A(t)=3600(1.075)^6\\A(t)=3600(1.543)\\A(t)=5555.88$

So, After 6 years the investment is $5555.88

Keywords: Compound Interest formula

Learn more about Compound Interest formula at:

#learnwithBrainly

8 0

3 years ago

4z−(−3z)=<br> combining like terms

uranmaximum [27]

For combining like terms: it is 7z

3 0

3 years ago

Read 2 more answers

A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first r

Kryger [21]

The probability of occurrence for the events A, B and C is; 1/4.

<h3>What is the probability of occurrence of.the described events?</h3>

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.