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Setler [38]
3 years ago
11

Two trains, Train A and Train B, simultaneously depart Station A and Station B. Station A and Station B are 252.5 miles apart fr

om each other. Train A is moving at 124.7mph towards Station B, and Train B is moving at 253.5mph towards station A. If both trains departed at 10:00AM and it is now 10:08, how much longer until both trains pass each other?
Mathematics
1 answer:
omeli [17]3 years ago
4 0

-- The trains start moving at the same time.

-- The space between them is initially 252.5 miles.

-- They reduce the distance between them at the rate of (124.7+253.5)=378.2mph.

-- It will take them (252.5 / 378.2) = 0.6676 hour to meet.  

That's 40min 3.49sec .

-- After tooting and puffing toward each other for 8 minutes, they still have <em>32min 3.49sec</em> to go before they meet each other.  We're all hoping that they're on different tracks.  

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(6a)2 - b^2

(6a + b)(6a - b)

Hope that helps :)

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You are buying a party pack of chips for $14.50 with a 3% tax. How much do you pay in total?
myrzilka [38]

Answer:

Step-by-step explanation:

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kirill [66]
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3 years ago
Sylas loves cookies! If he bought 5 cookies for $6.65, how many cookies<br> could he buy with $20?
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Answer:

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1 year ago
A line with a slope of -2/5 that passes through the point (-10,8)
slamgirl [31]

Step-by-step explanation:

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y-y_1=m(x-x_1)

Plug in the values into the equation

y - 8 =  -  \frac{2}{3} (x - ( - 10)) \\ y - 8 =  -  \frac{2}{3}( x + 10) \\

y - 8 =  -  \frac{2}{3} x  -  \frac{20}{ 3 }  \\ y =  -  \frac{2}{3} x -  \frac{20}{3}  + 8 \\

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To solve for x-intercept , Arrange the values in

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To find x-intercept .let y = 0 in the above equation

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