Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Photosynthesis is a process used by plants and other organisms to convert light energy into chemical chemical energy that can later be released to fuel the organisms activities.
If you're talking about eukaryotic cells then it's the cell wall. If it's a prokaryotic cell sometimes the slime layer secreted by some bacteria may harden and form a capsule around the bacterial cell.
Hope i helped!
Q1. The answer is 53 chromosomes
Zebra has 44 diploid chromosomes (2n = 44). Zebra's gametes are haploid, so they will have 22 chromosomes (n = 22).
Donkey has 62 diploid chromosomes (2n = 62). Zebra's gametes are haploid, so they will have 31 chromosomes (n = 31).
After fusion of zebra's gamete (n = 22) and donkey's gamete (n = 31), the zonkey's zygote will have 22 + 31 = 53 chromosomes
Q2 and Q3. In the meiosis, the number of chromosomes is reduced by half. Since zonkey has 53 chromosomes, after meiosis it should have 53/2 chromosomes, which is not the whole number. This is the reason why they cannot produce normal gametes that will result, after the fusion, in the production of normal diploid zygote
