Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am
Answer:
x= -4 & y=-12
Step-by-step explanation:
multiply y=3x by 2
giving you 2y=6x
subtracting 2y=x+20 from 2y =6x
=> 5x=-20
dividing through by 5
=> x=-4
put x=-4 into y=3x
=> y=3(-4)
<em>y</em><em>=</em><em>-12</em>
Answer:
$3 for Syd and $5 for Mark
Step-by-step explanation:
when Mark worked 8 hours and Syd worked 10 hours they earned $80
when Mark worked 9h Syd worked 5h they earned $65
we can make a equation out of these information
8M + 10S = $80
9M + 5S = $65 we can use the systems of equations by eliminating method
multiply second equation by -2
-2 × (9M + 5S) = $65
-18M - 10S = -$130 now add up the new equation with the first one
8M + 10S - 18M - 10S = $80 - $130 (10S will eliminate -10S)
-10M = -$50
10M = $50
M = $5
we can use hourly rate we found for M (Mark) to find the hourly rate for S (Syd)
9×5 + 5S = $65
45 + 5S = $65
5S = $15
S = $3
Answer:
- (2^9)
Step-by-step explanation:
-(2^6)(2^3)
We know a^b * a^c = a^( b+c)
- ( 2 ^ (6+3))
- (2^9)
