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ivann1987 [24]
3 years ago
13

Please solve |x-7| = 6

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

The answer x=13 or x=1

Step-by-step explanation:

Let's solve your equation step-by-step.

|x−7|=6

Solve Absolute Value.

|x−7|=6

We know eitherx−7=6orx−7=−6

x−7=6(Possibility 1)

x−7+7=6+7(Add 7 to both sides)

x=13

x−7=−6(Possibility 2)

x−7+7=−6+7(Add 7 to both sides)

x=1

Answer:

x=13 or x=1

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Which set of points includes all of the solutions for y = 5/2x + 3/2?
Firdavs [7]

Answer:

Choice A: (x,\frac{5}{2}x+ \frac{3}{2} ). for all real numbers.

Step-by-step explanation:

We are looking for points on the x-y plane which satisfy the equation y = 5/2x + 3/2, and these point are all those that lie on the graph of the equation, which are points (x,y) = (x,\frac{5}{2}x+ \frac{3}{2} ).

Looking at the other choices we see that choice B gives only 3 points, and regardless of whether they lie on the graph of y or not, this choice cannot be correct because 3 points are not all solutions.

The same goes for choice D.

And choice C is just the whole of x-y plane, therefore this cannot be the answer because not every point on the x-y plane is a solution to  y = 5/2x + 3/2

8 0
3 years ago
What’s the gcf of 2x+6?
Amiraneli [1.4K]

Answer:

25

Step-by-step explanation:

7 0
3 years ago
PLZZ help me with this I will give brilliantis to whoever gets it right
blagie [28]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
What is the simplest form of 0.875 as a fraction
alexandr402 [8]
Answer:

0.875 is equivalent to 7/8

Leave a thanks if this helped
5 0
3 years ago
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