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Len [333]
3 years ago
12

The mean high temperature on a particular day in January is 31 degrees F and the standard deviation is 8.7 degrees. One year, th

e temperature was 52 degrees F on that day. What is the Z-score for that day's temperature? Round to the appropriate number of decimal places for Z-scores. Is this temperature significantly high? (greater than 2)​
Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

jsjs gnckdoesosensjkcjbdjd

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Find the values of x and y using the give chord, secant, and tangent lengths
garri49 [273]

Answer: 7

Step-by-step explanation:

7

3 0
3 years ago
Zoe made a scale drawing of a house and its lot. She used a scale of 1 inch : 3 feet. In real life, the backyard is 45 feet wide
stellarik [79]
I believe the answer is 15 inches

45/3=15
7 0
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H(x) = 3x-4 what is h(6)
lina2011 [118]

Answer:

14

Step-by-step explanation:

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Solve the Anti derivative.​
Alex Ar [27]

Answer:

\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]:                                                                \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration:                                                                                                           \displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx<u />

<u />

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Factor fraction denominator:                                                         \displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx
  2. [Integral] Integration Property - Multiplied Constant:                                   \displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Substitute u-du:                                                                               \displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du
  2. [Integral] Trig Integration:                                                                               \displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C
  3. [Integral] Simplify:                                                                                           \displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C
  4. [integral] Multiply:                                                                                           \displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C
  5. [Integral] Back-Substitute:                                                                             \displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0
2 years ago
Scott wants to cover his patio with concrete pavers. If the patio is shaped like a trapezoid whose bases are 11 feet and 13 feet
GenaCL600 [577]

<u><em>Answer:</em></u>

Scott will need 168 ft² of pavers to cover his patio

<u><em>Explanation:</em></u>

Scott wants to cover a trapezoid-shaped patio

<u>This means that:</u>

To get the number of square feet of pavers he'll need, we need to get the area of his patio

<u>Area of trapezium id calculated as follows:</u>

Area = \frac{base_{1}+base_{2}}{2} * height

<u>We are given that:</u>

base₁ = 11 ft

base₂ = 13 ft

height = 14 ft

<u>We now substitute with the givens to get the area as follows:</u>

Area = \frac{11+13}{2} * 14 = 168ft^2

<u>This means that:</u>

Scott will need 168 ft² of pavers to cover his patio

Hope this helps :)

5 0
3 years ago
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