Answer:
Step-by-step explanation:
No solution. Lines M and P have the same slope but different y-intercepts., so they are parallel lines.
Parallel lines don’t intersect each other, so there is no solution.
Answer:
-(33+110z)/10z
Step-by-step explanation:
(-7/2z +4)+(1/5z -15)
from BODMAS, solving the one in the bracket
First(-7/2z +4)+(1/5z -15)
Find the Lcm
[-7/2z +4] +[1/5z -15]
(7+8z)/2z +(1-75z)/5z
find the Lcm which is 10z
[5(-7+8z) + 2(1-75z)]/10z
[(-35+40z)+(2-150z)]10z
(-35+2+40z-150z)/10z
(-33-110z)/10z
-(33+110z)/10z
Answer:
The correct answer is second quadrant.
Step-by-step explanation:
Vertices of J ≡ (3 , -5) which shows J is in fourth quadrant. When J is reflected across the line y = -1, the point J moves to first quadrant as J' with coordinates (3 , 3).
Vertices of K ≡ (-8 , -1) which shows K is in third quadrant. When K is reflected across the line y = -1, the point K remains where it is (in the third quadrant) as it is on the line y = -1 only.
Vertices of L ≡ (5 , 1) which shows L is in first quadrant. When L is reflected across the line y = -1, the point L moves to fourth quadrant as L' with coordinates (5 , -3).
Thus each of the first, fourth and third quadrant contains a vertex except the second quadrant.
This is just a line there are infinitely many solutions or points...for every value of x there is a value for y which is three times x. Pick any x solve for y and that is one of the infinite number of ordered pairs produced by the equation.
y=3x (0,0),(1,3),(2,6),(3,9).....................
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