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3 years ago

What is the function of the system shown in the diagram?

Chemistry

1 answer:

Akimi4 [234]3 years ago

6 0

Answer:

the answer is carrying oxygenated blood and nutrients to cells

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How many molecules does 88 grams CO2 contain? A) 1.2 X 1024 B) 1.8 X 1024 C) 3.0 X 1023 D) 6.0 X 1023

mylen [45]

Hey there!:

Molar mass CO2 = 44.01 g/mol

44.01 g CO2 ------------------- 6.02*10²² molecules CO2

88 g CO2 ------------------------ y

y = 88 * ( 6.02*10²² ) / 44.01

y = 5.29*10²⁵ / 44.01

y = 1.2 * 10²⁴ molecules of CO2

Answer A

Hope that helps!

7 0

3 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

"how many moles of calcium atoms are in 2.5 moles of calcium carbonate caco3"

Montano1993 [528]

Answer: -

2.5 moles of calcium atoms are in 2.5 moles of calcium carbonate CaCO₃

Explanation: -

In order to solve such types of problems, the first step would be to write the chemical formula of the compound.

The chemical formula of calcium carbonate = CaCO₃

The chemical symbol of Calcium is Ca.

From the formula of calcium carbonate we can see that

1 mole of CaCO₃ has 1 mole of Ca

2.5 mole of CaCO₃ has $\frac{1 mole Ca }{1 mole CaCO₃} x 2.5 mole CaCO₃$

= 2.5 mol of Ca.

∴2.5 moles of calcium atoms are in 2.5 moles of calcium carbonate CaCO₃

5 0

3 years ago

An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.

Harman [31]

Answer:

HCl conc.= 6.0mol/L

Explanation:

From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,

4 0

4 years ago

Suppose you were calibrating a 100.0 ml volumetric flask using distilled water. the flask temperature was at 20°c, and you assum

kicyunya [14]

The density of water at 12°C is lower than the density of water at 20°C.

Now density is related to volume as per: density = mass / volume =>

mass = volume * density.

So, the greaer the density the higher the mass of the same volume of water.

Therefore, 100.0 ml of water at 12°C has a mass greater than 100.00 ml of water at 20 °C.

4 0

4 years ago