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3 years ago

How many molecules are there in 322 grams of Cu(NO3)2

Chemistry

1 answer:

mr_godi [17]3 years ago

3 0

cu=1*63g=63g
n=2*14g=28g
o=6*16g=96g
total=187g/mol
122(1 mol/187)(6.02*10^23)= 3.92*10^23

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Complete the sentences to explain why the molecule ch3f is polar.

Lelu [443]

A group of environmentalists were discussing the benefits and drawbacks associated with using fossil fuels. Which argument best fits the conversation?
Fossil fuels are cheaper than alternative forms of energy.Fossil fuel reserves will never be depleted.Fossil fuels are easily renewed. Fossil fuel use does not affect the environment.

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3 years ago

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what is the molecular formula of benzoyl peroxide (c7h5o2) of the molecular mass is 0.242 kg/mol?(show work please)

AfilCa [17]

Answer : The molecular formula of benzoyl peroxide is $C_{14}H_{10}O_4$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

As we are given that the molar mass of compound is, 0.242 kg/mol.

Molecular mass = 0.242 kg/mol = 242 g/mol (1 kg = 1000 g)

The empirical mass of $C_7H_5O_2$ = 7(12) + 5(1) + 2(16) = 121 g/eq

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

$n=\frac{242}{121}$

$n=2$

Molecular formula = $(C_7H_5O_2)_n$ = $(C_7H_5O_2)_2$ = $C_{14}H_{10}O_4$

Thus, the molecular formula of benzoyl peroxide is $C_{14}H_{10}O_4$

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2 years ago

Help I’m so confused

ira [324]

Answer:

Me too. What is this for? A Lab. You are missing some kind of key info bud.

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Bogdan [553]

Don't touch your eyes.

Never taste-test unless the teacher tells you to.

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Wear proper lab clothes.

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Report accidents to the teacher right away!

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3 years ago

formic acid buffer containing 0.50 M HCOOH and 0.50 M HCOONa has a pH of 3.77. What will the pH be after 0.010 mol of NaOH has b

HACTEHA [7]

Answer:

pH = 3.95

Explanation:

It is possible to calculate the pH of a buffer using H-H equation.

pH = pka + log₁₀ [HCOONa] / [HCOOH]

If concentration of [HCOONa] = [HCOOH] = 0.50M and pH = 3.77:

3.77 = pka + log₁₀ [0.50] / [0.50]

3.77 = pka

Knowing pKa, the NaOH reacts with HCOOH, thus:

HCOOH + NaOH → HCOONa + H₂O

That means the NaOH you add reacts with HCOOH producing more HCOONa.

Initial moles of 100.0mL = 0.1000L:

[HCOOH] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOOH

[HCOONa] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOONa

After the reaction, moles of each species is:

0.0500moles HCOOH - 0.010 moles NaOH (Moles added of NaOH) = 0.0400 moles HCOOH

0.0500moles HCOONa + 0.010 moles NaOH (Moles added of NaOH) = 0.0600 moles HCOONa

With these moles of the buffer, you can calculate pH:

pH = 3.77 + log₁₀ [0.0600] / [0.0400]

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3 years ago