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3 years ago

12

Plz help... answer this question!

1 answer:

Mkey [24]3 years ago

5 0

Answer:

B

Explanation:

Because element is made up of only one type of atoms and figure b show only one type of atoms.

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Which of these reactions can be classified as double replacement reactions?

Kryger [21]

1) Zn + 2 HCl = ZnCl2 + H2 ( <span>single replacement )

2) </span>2 NaCl + F2 = 2 NaF + Cl2 ( <span>single replacement )

3) </span>2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3 ( <span>double replacement )

4) </span>2 K + MgBr2 = 2 KBr + Mg ( <span>single replacement )

Answer 3

hope this helps!</span>

4 0

3 years ago

Assuming the volumes are additive, what is the [Cl−] in a solution obtained by mixing 297 mL of 0.675 M KCl and 664 mL of 0.338

Elden [556K]

<u>Answer:</u> The concentration of chloride ions in the solution obtained is 0.674 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

<u>For KCl:</u>

Molarity of KCl solution = 0.675 M

Volume of solution = 297 mL

Putting values in equation 1, we get:

$0.675=\frac{\text{Moles of KCl}\times 1000}{297}\\\\\text{Moles of KCl}=\frac{(0.675mol/L\times 297)}{1000}=0.200mol$

1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion

Moles of chloride ions in KCl = 0.200 moles

<u>For magnesium chloride:</u>

Molarity of magnesium chloride solution = 0.338 M

Volume of solution = 664 mL

Putting values in equation 1, we get:

$0.338=\frac{\text{Moles of }MgCl_2\times 1000}{664}\\\\\text{Moles of }MgCl_2=\frac{(0.338mol/L\times 664)}{1000}=0.224mol$

1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion

Moles of chloride ions in magnesium chloride = $(2\times 0.224)=0.448mol$

Calculating the chloride ion concentration, we use equation 1:

Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles

Total volume of the solution = (297 + 664) mL = 961 mL

Putting values in equation 1, we get:

$\text{Concentration of chloride ions}=\frac{0.648mol\times 1000}{961}\\\\\text{Concentration of chloride ions}=0.674M$

Hence, the concentration of chloride ions in the solution obtained is 0.674 M

5 0

3 years ago

How many atoms are in 6.7 moles of iron?

sineoko [7]

Answer:

4.034x10^24 atoms

Explanation:

6.7 x 6.023x10^23 = 4.034x10^24 atoms

6 0

3 years ago

Read 2 more answers

According to the following reaction, how many moles of carbon dioxide will be formed upon the complete reaction of 22.7 grams of

AnnZ [28]

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7 0

3 years ago

What do you think is responsible for the color produced in the flame, the metal atom or what is attached to the metal atom?

zlopas [31]

Answer:

metal Atom

Explanation:

every transition metal atom are responsible for the flame color. Some metal are also confirmed by flame test.

7 0

3 years ago