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Virty [35]
2 years ago
12

Plz help... answer this question!

Chemistry
1 answer:
Mkey [24]2 years ago
5 0

Answer:

B

Explanation:

Because element is made up of only one type of atoms and figure b show only one type of atoms.

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What volume does 0.482 mol of gas occupy at a pressure of 719 mmHg at 56 ∘C?
kozerog [31]

Answer:

The volume is 13, 69 L

Explanation:

We use the formula PV=nRT. We convert the temperature in Celsius into Kelvin and the pressure in mmHg into atm.

0°C= 273K---> 56°C= 56 + 273= 329K

760 mmHg----1 atm

719 mmHg----x= (719 mmHgx 1 atm)/760 mmHg= 0,95 atm

PV=nRT ---> V= (nRT)/P

V=( 0,482 molx 0,082 l atm/K mol x 329K)/0,95 atm

<em>V=13,68778526 L</em>

7 0
3 years ago
CCC Matter and Energy The dashed curve shows
Bogdan [553]

The amount of absorption force is not same at all time and at all where .

It has difference at different time periods

So during those the curve goes up and down and repeat this flow

So there are dips

7 0
2 years ago
Explain the electrolysis of acidified water​
Andrew [12]

Answer:

yqaeh

Explanation:

Electrolysis of acidified water

Water is a poor conductor of electricity, but it does contain some hydrogen ions , H +, and hydroxide ions, OH -. These ions are formed when a small proportion of water molecules naturally dissociate . ... H + ions are attracted to the cathode , gain electrons and form hydrogen gas.

8 0
2 years ago
According to the law of conservation of mass, the total mass of the reactants is
yarga [219]

Answer:

is equal to the total number of products

Explanation:

3 0
2 years ago
The reaction between solid white phosphorous and oxygen produces solid tetraphosphorous decaoxide (P4010).
Alchen [17]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of phosphorus = 25.0 g

Mass of oxygen = 50.0 g

What is limiting reactant ?

Solution:

Chemical equation:

P₄   +  5O₂       →      P₄O₁₀

Number of moles of P₄:

Number of moles = mass/molar mass

Number of moles = 25.0 g/ 123.89 g/mol

Number of moles = 0.20 mol

Number of moles of  O₂:

Number of moles = mass/molar mass

Number of moles = 50.0 g/ 32 g/mol

Number of moles = 1.56 mol

now we will compare the moles of reactants with product:

        P₄          :            P₄O₁₀

         1           :              1

      0.20       :          0.20

      O₂           :         P₄O₁₀

       5            :         1

     1.56         :        1/5×1.56 = 0.312 mol

Less number of moles of product are formed by the oxygen thus it will act as limiting reactant.

8 0
3 years ago
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