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Damm [24]
3 years ago
9

When he was measuring herbs on his balance scale, Neville placed a 1/2 gram weight, then a 1/5 gram weight, and finally a 1/8 gr

am weight before the scale balanced. How much did his herbs weigh?
Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:  \dfrac{33}{40}\ gm

Step-by-step explanation:

Given

Neville place three weights in the sequence

\dfrac{1}{2}\ gm,\dfrac{1}{5}\ gm,\dfrac{1}{8}\ gm

The total weight of the three weights is

\Rightarrow \dfrac{1}{2}+\dfrac{1}{5}+\dfrac{1}{8}=\dfrac{20+8+5}{40}\\\\\Rightarrow \dfrac{33}{40}\ gm

Thus, herbs weigh  \frac{33}{40}\ gm

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<h3>Answer:</h3>

8

<h2><u>STEPS:</u></h2>

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