Answer:
Step-by-step explanation:
The equation of a linear function in point-slope form is y – y1 = m(x – x1)
The point is A (x1 , y1)
in this exercice : x1 = 3 and y1 =2
let A(3,2) B(-9,6)
the slope is : m = (YB - YA)/(XB -XA)
(6-2)/(-9-3) =4/(-12) = -1/3
the slope is m = -1/3
The equation is : y – y1 = m(x – x1)
y-2 =-1/3 ( x-3)
or : 3y-6 = -x+3
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Step-by-step explanation:
Desmos Graphing Calculator
The kite is approximately 78.80 feet off of the ground.
Explanation: If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. sin
θ
=
o
p
p
h
y
p
sin
52
o
=
h
100
f
t
100
sin
52
o
=
h
100
(
0.7880
)
=
h
78.80
f
t
=
h
Answer:
d =
Step-by-step explanation:
Use the distance formula: d =
A (0, 0)
B ( 1, 3)
d =
d =
d =
d =